Optimal. Leaf size=232 \[ -\frac{i b e \text{PolyLog}(2,-i c x)}{2 d^2}+\frac{i b e \text{PolyLog}(2,i c x)}{2 d^2}+\frac{i b e \text{PolyLog}\left (2,1-\frac{2}{1-i c x}\right )}{2 d^2}-\frac{i b e \text{PolyLog}\left (2,1-\frac{2 c (d+e x)}{(1-i c x) (c d+i e)}\right )}{2 d^2}-\frac{e \log \left (\frac{2}{1-i c x}\right ) \left (a+b \tan ^{-1}(c x)\right )}{d^2}+\frac{e \left (a+b \tan ^{-1}(c x)\right ) \log \left (\frac{2 c (d+e x)}{(1-i c x) (c d+i e)}\right )}{d^2}-\frac{a+b \tan ^{-1}(c x)}{d x}-\frac{a e \log (x)}{d^2}-\frac{b c \log \left (c^2 x^2+1\right )}{2 d}+\frac{b c \log (x)}{d} \]
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Rubi [A] time = 0.241335, antiderivative size = 232, normalized size of antiderivative = 1., number of steps used = 14, number of rules used = 12, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.632, Rules used = {4876, 4852, 266, 36, 29, 31, 4848, 2391, 4856, 2402, 2315, 2447} \[ -\frac{i b e \text{PolyLog}(2,-i c x)}{2 d^2}+\frac{i b e \text{PolyLog}(2,i c x)}{2 d^2}+\frac{i b e \text{PolyLog}\left (2,1-\frac{2}{1-i c x}\right )}{2 d^2}-\frac{i b e \text{PolyLog}\left (2,1-\frac{2 c (d+e x)}{(1-i c x) (c d+i e)}\right )}{2 d^2}-\frac{e \log \left (\frac{2}{1-i c x}\right ) \left (a+b \tan ^{-1}(c x)\right )}{d^2}+\frac{e \left (a+b \tan ^{-1}(c x)\right ) \log \left (\frac{2 c (d+e x)}{(1-i c x) (c d+i e)}\right )}{d^2}-\frac{a+b \tan ^{-1}(c x)}{d x}-\frac{a e \log (x)}{d^2}-\frac{b c \log \left (c^2 x^2+1\right )}{2 d}+\frac{b c \log (x)}{d} \]
Antiderivative was successfully verified.
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Rule 4876
Rule 4852
Rule 266
Rule 36
Rule 29
Rule 31
Rule 4848
Rule 2391
Rule 4856
Rule 2402
Rule 2315
Rule 2447
Rubi steps
\begin{align*} \int \frac{a+b \tan ^{-1}(c x)}{x^2 (d+e x)} \, dx &=\int \left (\frac{a+b \tan ^{-1}(c x)}{d x^2}-\frac{e \left (a+b \tan ^{-1}(c x)\right )}{d^2 x}+\frac{e^2 \left (a+b \tan ^{-1}(c x)\right )}{d^2 (d+e x)}\right ) \, dx\\ &=\frac{\int \frac{a+b \tan ^{-1}(c x)}{x^2} \, dx}{d}-\frac{e \int \frac{a+b \tan ^{-1}(c x)}{x} \, dx}{d^2}+\frac{e^2 \int \frac{a+b \tan ^{-1}(c x)}{d+e x} \, dx}{d^2}\\ &=-\frac{a+b \tan ^{-1}(c x)}{d x}-\frac{a e \log (x)}{d^2}-\frac{e \left (a+b \tan ^{-1}(c x)\right ) \log \left (\frac{2}{1-i c x}\right )}{d^2}+\frac{e \left (a+b \tan ^{-1}(c x)\right ) \log \left (\frac{2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{d^2}+\frac{(b c) \int \frac{1}{x \left (1+c^2 x^2\right )} \, dx}{d}-\frac{(i b e) \int \frac{\log (1-i c x)}{x} \, dx}{2 d^2}+\frac{(i b e) \int \frac{\log (1+i c x)}{x} \, dx}{2 d^2}+\frac{(b c e) \int \frac{\log \left (\frac{2}{1-i c x}\right )}{1+c^2 x^2} \, dx}{d^2}-\frac{(b c e) \int \frac{\log \left (\frac{2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{1+c^2 x^2} \, dx}{d^2}\\ &=-\frac{a+b \tan ^{-1}(c x)}{d x}-\frac{a e \log (x)}{d^2}-\frac{e \left (a+b \tan ^{-1}(c x)\right ) \log \left (\frac{2}{1-i c x}\right )}{d^2}+\frac{e \left (a+b \tan ^{-1}(c x)\right ) \log \left (\frac{2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{d^2}-\frac{i b e \text{Li}_2(-i c x)}{2 d^2}+\frac{i b e \text{Li}_2(i c x)}{2 d^2}-\frac{i b e \text{Li}_2\left (1-\frac{2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{2 d^2}+\frac{(b c) \operatorname{Subst}\left (\int \frac{1}{x \left (1+c^2 x\right )} \, dx,x,x^2\right )}{2 d}+\frac{(i b e) \operatorname{Subst}\left (\int \frac{\log (2 x)}{1-2 x} \, dx,x,\frac{1}{1-i c x}\right )}{d^2}\\ &=-\frac{a+b \tan ^{-1}(c x)}{d x}-\frac{a e \log (x)}{d^2}-\frac{e \left (a+b \tan ^{-1}(c x)\right ) \log \left (\frac{2}{1-i c x}\right )}{d^2}+\frac{e \left (a+b \tan ^{-1}(c x)\right ) \log \left (\frac{2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{d^2}-\frac{i b e \text{Li}_2(-i c x)}{2 d^2}+\frac{i b e \text{Li}_2(i c x)}{2 d^2}+\frac{i b e \text{Li}_2\left (1-\frac{2}{1-i c x}\right )}{2 d^2}-\frac{i b e \text{Li}_2\left (1-\frac{2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{2 d^2}+\frac{(b c) \operatorname{Subst}\left (\int \frac{1}{x} \, dx,x,x^2\right )}{2 d}-\frac{\left (b c^3\right ) \operatorname{Subst}\left (\int \frac{1}{1+c^2 x} \, dx,x,x^2\right )}{2 d}\\ &=-\frac{a+b \tan ^{-1}(c x)}{d x}+\frac{b c \log (x)}{d}-\frac{a e \log (x)}{d^2}-\frac{e \left (a+b \tan ^{-1}(c x)\right ) \log \left (\frac{2}{1-i c x}\right )}{d^2}+\frac{e \left (a+b \tan ^{-1}(c x)\right ) \log \left (\frac{2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{d^2}-\frac{b c \log \left (1+c^2 x^2\right )}{2 d}-\frac{i b e \text{Li}_2(-i c x)}{2 d^2}+\frac{i b e \text{Li}_2(i c x)}{2 d^2}+\frac{i b e \text{Li}_2\left (1-\frac{2}{1-i c x}\right )}{2 d^2}-\frac{i b e \text{Li}_2\left (1-\frac{2 c (d+e x)}{(c d+i e) (1-i c x)}\right )}{2 d^2}\\ \end{align*}
Mathematica [A] time = 0.141304, size = 223, normalized size = 0.96 \[ -\frac{-i b e x \text{PolyLog}\left (2,\frac{e (1-i c x)}{e+i c d}\right )+i b e x \text{PolyLog}\left (2,-\frac{e (c x-i)}{c d+i e}\right )+i b e x \text{PolyLog}(2,-i c x)-i b e x \text{PolyLog}(2,i c x)-2 a e x \log (d+e x)+2 a d+2 a e x \log (x)+b c d x \log \left (c^2 x^2+1\right )-i b e x \log (1-i c x) \log \left (\frac{c (d+e x)}{c d-i e}\right )+i b e x \log (1+i c x) \log \left (\frac{c (d+e x)}{c d+i e}\right )-2 b c d x \log (x)+2 b d \tan ^{-1}(c x)}{2 d^2 x} \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.07, size = 321, normalized size = 1.4 \begin{align*}{\frac{ae\ln \left ( ecx+dc \right ) }{{d}^{2}}}-{\frac{a}{dx}}-{\frac{ae\ln \left ( cx \right ) }{{d}^{2}}}+{\frac{b\arctan \left ( cx \right ) e\ln \left ( ecx+dc \right ) }{{d}^{2}}}-{\frac{b\arctan \left ( cx \right ) }{dx}}-{\frac{b\arctan \left ( cx \right ) e\ln \left ( cx \right ) }{{d}^{2}}}-{\frac{{\frac{i}{2}}be{\it dilog} \left ( 1+icx \right ) }{{d}^{2}}}+{\frac{{\frac{i}{2}}be{\it dilog} \left ( 1-icx \right ) }{{d}^{2}}}+{\frac{{\frac{i}{2}}be\ln \left ( cx \right ) \ln \left ( 1-icx \right ) }{{d}^{2}}}-{\frac{{\frac{i}{2}}be}{{d}^{2}}{\it dilog} \left ({\frac{ie+ecx}{ie-dc}} \right ) }-{\frac{bc\ln \left ({c}^{2}{x}^{2}+1 \right ) }{2\,d}}+{\frac{cb\ln \left ( cx \right ) }{d}}+{\frac{{\frac{i}{2}}be\ln \left ( ecx+dc \right ) }{{d}^{2}}\ln \left ({\frac{ie-ecx}{dc+ie}} \right ) }+{\frac{{\frac{i}{2}}be}{{d}^{2}}{\it dilog} \left ({\frac{ie-ecx}{dc+ie}} \right ) }-{\frac{{\frac{i}{2}}be\ln \left ( ecx+dc \right ) }{{d}^{2}}\ln \left ({\frac{ie+ecx}{ie-dc}} \right ) }-{\frac{{\frac{i}{2}}be\ln \left ( cx \right ) \ln \left ( 1+icx \right ) }{{d}^{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} a{\left (\frac{e \log \left (e x + d\right )}{d^{2}} - \frac{e \log \left (x\right )}{d^{2}} - \frac{1}{d x}\right )} + 2 \, b \int \frac{\arctan \left (c x\right )}{2 \,{\left (e x^{3} + d x^{2}\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{b \arctan \left (c x\right ) + a}{e x^{3} + d x^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{b \arctan \left (c x\right ) + a}{{\left (e x + d\right )} x^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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